-2y^2+y=1

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Solution for -2y^2+y=1 equation: 



-2y^2+y=1

We move all terms to the left:

-2y^2+y-(1)=0

a = -2; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·(-2)·(-1)
Δ = -7
Delta is less than zero, so there is no solution for the equation

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